-sin^2x-3sinx+cos^2x=2

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Solution for -sin^2x-3sinx+cos^2x=2 equation:


Simplifying
-1sin2x + -3sinx + cos2x = 2

Reorder the terms:
cos2x + -3insx + -1in2sx = 2

Solving
cos2x + -3insx + -1in2sx = 2

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '3insx' to each side of the equation.
cos2x + -3insx + 3insx + -1in2sx = 2 + 3insx

Combine like terms: -3insx + 3insx = 0
cos2x + 0 + -1in2sx = 2 + 3insx
cos2x + -1in2sx = 2 + 3insx

Add 'in2sx' to each side of the equation.
cos2x + -1in2sx + in2sx = 2 + 3insx + in2sx

Combine like terms: -1in2sx + in2sx = 0
cos2x + 0 = 2 + 3insx + in2sx
cos2x = 2 + 3insx + in2sx

Divide each side by 'os2x'.
c = 2o-1s-2x-1 + 3ino-1s-1 + in2o-1s-1

Simplifying
c = 2o-1s-2x-1 + 3ino-1s-1 + in2o-1s-1

Reorder the terms:
c = 3ino-1s-1 + in2o-1s-1 + 2o-1s-2x-1

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